work = the change in energy = (potential final - potential initial ) + (kenetic final - kenetic initial) = (mgh1 - mgh2) + (1/2 mv(squared)1- 1/2 mv(squared)2)</p> you got this!</p>
holy shit, I had the worst teacher (and class) for physics my junior year, and yet somehow I aced that class and the NY regents exam.</p> I don't know how I passed it, because that thing Jigga put up makes no sense to me now. I think after graduating, my brain got emptied out or something.</p> anyways, Good luck!!</p>
Wow, grad school in physics- I'm taking classical and quantum waves right now, I may have a bunch of questions for you over the next couple of years. Good luck on the test!</p>
Good luck ly_ying, I spent about six months studying for mine.</p> If it helps any the Kaplan program is great though kind of expensive.</p>
Good luck on the physics exam.</p> I should be studying right now for an actuarial-type test that I'm taking in Nov.</p> It's hard to get the ol' grey matter to focus.</p>
<div class='quotetop'>QUOTE (GMJigga)</div><div class='quotemain'></p> work = the change in energy = (potential final - potential initial ) + (kenetic final - kenetic initial) = (mgh1 - mgh2) + (1/2 mv(squared)1- 1/2 mv(squared)2)</p> you got this!</p> </div></p> </p> Ah yes. But the potential for an electric charge is kqq/r.</p> And the potential energy in a spring is 1/2 k (deltaX)^2.</p> And there's rotational kinetic energy = 1/2 I * omega^2.</p> And of course, if you want to start talking about Lagrangians, you actually need to start looking at Kinetic MINUS Potential energy.</p> And so on, and so forth.</p> The hardest stuff was all the random stuff about electrons and atoms they expected us to know. Allowable spin shifts in dipole transitions? Uhhh, skip to the block problems, thank you very much.</p>
<div class='quotetop'>QUOTE (Teaneck_Armory_Guy)</div><div class='quotemain'></p> Good luck on the physics exam.</p> I should be studying right now for an actuarial-type test that I'm taking in Nov.</p> It's hard to get the ol' grey matter to focus.</p> </div></p> </p> Physics is hard, but being an actuary just sounds brutal.</p> </p> <div class='quotetop'>QUOTE (Tyler Durden)</div><div class='quotemain'>Narrator: A new car built by my company leaves somewhere traveling at 60 mph. The rear differential locks up. The car crashes and burns with everyone trapped inside. Now, should we initiate a recall? Take the number of vehicles in the field, A, multiply by the probable rate of failure, B, multiply by the average out-of-court settlement, C. A times B times C equals X. If X is less than the cost of a recall, we don't do one. Business woman on plane: Are there a lot of these kinds of accidents? Narrator: You wouldn't believe. Business woman on plane: Which car company do you work for? Narrator: A major one.</div></p>
