Theirs tutoring at my school, and I really want to go, but I don't have a ride back home!</p> So guess who's gonna tutor me???</p> </p> YOU GUYS!!!</p>
Nice....now.</p> 1. Average Rate of Change- Find the average rate of change of f(x) = 1 + sin x over the interval [0. 2pi].</p> 2. Rate of Change- Find the instantaneous rate of change of the surface area S = 6x^2 of a cube with respect to the edge length x at x = a</p> Not sure how hard/easy it is. I'm supposed to algebraicly solve it. Just drawing the graph, and then using the tangent would be nice...but our book would like us to do it a way that it has absolutely zero examples on how to do it that way. How can there be a rate of change without time?</p>
<div class='quotetop'>QUOTE (o.iatlhawksfan)</div><div class='quotemain'> Can somebody help me with Triangles LOL!</p> </div></p> Postanexampleproblemortwo.</p> </p>
<div class='quotetop'>QUOTE (BG7 Lavigne)</div><div class='quotemain'></p> Nice....now.</p> 1. Average Rate of Change- Find the average rate of change of f(x) = 1 + sin x over the interval [0. 2pi].</p> 2. Rate of Change- Find the instantaneous rate of change of the surface area S = 6x^2 of a cube with respect to the edge length x at x = a</p> Not sure how hard/easy it is. I'm supposed to algebraicly solve it. Just drawing the graph, and then using the tangent would be nice...but our book would like us to do it a way that it has absolutely zero examples on how to do it that way. How can there be a rate of change without time?</p> </div></p> 1. Get x,y values in that function and then its a matter of getting rise over run. the difference between the x's over the difference in the y's. It won't matter which one you put 'first' (the zero or 2pi value) just as long as your consistent in the numerator and denominator.</p> 2. This requires a derivative for the function. Then plug in A. (hint: 12a)</p> </p>
<div class='quotetop'>QUOTE (BG7 Lavigne)</div><div class='quotemain'></p> Nice....now.</p> 1. Average Rate of Change- Find the average rate of change of f(x) = 1 + sin x over the interval [0. 2pi].</p> 2. Rate of Change- Find the instantaneous rate of change of the surface area S = 6x^2 of a cube with respect to the edge length x at x = a</p> Not sure how hard/easy it is. I'm supposed to algebraicly solve it. Just drawing the graph, and then using the tangent would be nice...but our book would like us to do it a way that it has absolutely zero examples on how to do it that way. How can there be a rate of change without time?</p> </div></p> algebraically? so does that mean find the derivatives?</p> if so, it's pretty easy. for the first problem, the derivative rules say the derivative of (one function + another function) = (the derivative of one function) + (the derivative of another function). so you break it down...for the first function, the derivative of a constant is 0 (zero). and for the second function, the derivative of sin is cos.</p> and for the second problem, you must use the power rule, that says : a*(x^n)= n*a*(x^(n-1)) ; where a=constant, and n=power.</p> </p>
<div class='quotetop'>QUOTE (o.iatlhawksfan)</div><div class='quotemain'></p> Can somebody help me with Triangles LOL!</p> </div></p> http://en.wikipedia.org/wiki/Congruence_(geometry)</p> Wikipedia helps...you guys should learn to use search engines to help you out. They're a great resource.</p> If you don't understand anything on Wikipedia, or have googled it and don't understand it, just ask questions. We'd love to help out.</p> </p>
Thanks very much. Ugh...I was just being dumb on that first one. Got it pretty easily...basic secant slope, y2-y1 / x2-x1....ugh...</p> That power rule works wonders.</p>
<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p> Anybody here know some Chemistry?</p> </div></p> I got a 96 in chem, but that was two years ago. I'd be happy to help if I can remember though.</p> </p>
<div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p> how do i find x:</p> -5sin(5x)=0</p> </p> I always have trouble with trig/algebra problems.</p> </div></p> Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p> So:</p> (-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p> (arcsin)(sin(5x)=0), will get you: 5x=0</p> (1/5)(5x=0), will get you: x=0</p> </p>
<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p> First what does this mean PV=nRT</p> </div></p> P = pressure V = volume n = number of moles R = gas constant (don't remember what it is) T = temperature in Kelvins</p> </p>
<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p> Do you know how to balance equations?</p> </div></p> Yea, if they're not too complex.</p> </p>
<div class='quotetop'>QUOTE (JCB)</div><div class='quotemain'></p> <div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p> how do i find x:</p> -5sin(5x)=0</p> </p> I always have trouble with trig/algebra problems.</p> </div></p> Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p> So:</p> (-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p> (arcsin)(sin(5x)=0), will get you: 5x=0</p> (1/5)(5x=0), will get you: x=0</p> </p> </div></p> That's why I got! and it didn't work. I have to use this online thing to do homework, and it tells you right away if the answer is wrong. It's so ridiculous, and the way the teacher is running the class is ridiculous.</p> </p>
<div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p> <div class='quotetop'>QUOTE (JCB)</div><div class='quotemain'></p> <div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p> how do i find x:</p> -5sin(5x)=0</p> </p> I always have trouble with trig/algebra problems.</p> </div></p> Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p> So:</p> (-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p> (arcsin)(sin(5x)=0), will get you: 5x=0</p> (1/5)(5x=0), will get you: x=0</p> </p> </div></p> That's why I got! and it didn't work. I have to use this online thing to do homework, and it tells you right away if the answer is wrong. It's so ridiculous, and the way the teacher is running the class is ridiculous.</p> </p> </div></p> It says that 0 as an answer is wrong? wtf?</p> </p>
<div class='quotetop'>QUOTE (o.iatlhawksfan)</div><div class='quotemain'></p> Can somebody help me with Triangles LOL!</p> </div></p> </p> I'll be happy to help</p>
