<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p> H2 02------->H2O+O2</p> </div></p> 2H2 02------->2H2O+O2</p> I think.</p> </p>
[quote name='JCB']</p> [quote name='peg182']</p> [quote name='JCB']</p> [quote name='peg182']</p> how do i find x:</p> -5sin(5x)=0</p> </p> I always have trouble with trig/algebra problems.</p> [/QUOTE]</p> Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p> So:</p> (-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p> (arcsin)(sin(5x)=0), will get you: 5x=0</p> (1/5)(5x=0), will get you: x=0</p> </p> [/QUOTE]</p> That's why I got! and it didn't work. I have to use this online thing to do homework, and it tells you right away if the answer is wrong. It's so ridiculous, and the way the teacher is running the class is ridiculous.</p> </p> [/QUOTE]</p> It says that 0 as an answer is wrong? wtf?</p> </p> [/QUOTE]</p> </p> Yeah, this online homework thing is ridiculous, and this class is ridiculous. I think I'm dropping, mainly because of the fact that the way it's set up, I'm not really learning anything. And the teacher sucks.</p>
<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p> H2 02------->H2O+O2</p> </div></p> 2 hydrogen peroxide molecules breaks down into 2 water molecules and 1 oxygen molecule</p> The key to solving this is to realize that there must be an even number of water molecules because there will always be an even number of oxygens coming from the peroxide.</p> </p>
<div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p> You don't multiply by arcsin, instead you must perform arcsin on each side</p> 5x=arcsin(0)</p> </div></p> </p> wouldn't the answer still be zero?</p>
<div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p> You don't multiply by arcsin, instead you must perform arcsin on each side</p> 5x=arcsin(0)</p> </div></p> Pssh, I hate math terms.</p> Either way, you get 5x=0</p> </p> </p>
Why I am having a hard time with multiplying, dividing, adding radicals? It's like 7th grade math isn't it? That's proof that math is no where close to being one of my strong points.</p>
So the one that JCB put is correct?I had something similar to his answer.OK I have a few things that I don't know what they are Temperature Scale, Acid and Base, gas law and conservation of mass.</p>
<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p> So the one that JCB put is correct?I had something similar to his answer.OK I have a few things that I don't know what they are Temperature Scale, Acid and Base, gas law and conservation of mass.</p> </div></p> Yes, it is correct</p> Go ahead and fire away.</p> </p>
<div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p> Remember sin(0) = 0, sin(pi) = 0, sin(2pi) = 0 etc</p> There are multiple solutions for x</p> </div></p> That's what I was thinking with the sin curve and such, but working with that equation, and solving for x algebraically, just gives you 0. Using the sin curve will give you infinite answers, but algebraically, you just get one answer, 0. Right? Or am I missing something completely obvious?</p> I've got a few derivative questions I'll ask tomorrow. This thread could be useful.</p> </p>
<div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p> Remember sin(0) = 0, sin(pi) = 0, sin(2pi) = 0 etc</p> There are multiple solutions for x</p> </div></p> any within [pi/10, 3pi/10]?</p> i can't figure any out within those parameters. I don't think there is a right answer there.</p> </p>
<div class='quotetop'>QUOTE (Kidd)</div><div class='quotemain'></p> Why I am having a hard time with multiplying, dividing, adding radicals? It's like 7th grade math isn't it? That's proof that math is no where close to being one of my strong points.</p> </div></p> Got an example?</p> </p>
<div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p> <div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p> Remember sin(0) = 0, sin(pi) = 0, sin(2pi) = 0 etc</p> There are multiple solutions for x</p> </div></p> any within [pi/10, 3pi/10]?</p> i can't figure any out within those parameters. I don't think there is a right answer there.</p> </div></p> 2pi/10 because sin( 5*2pi/10) = sin(pi) = 0</p> </p> </p> </p>
<div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p> <div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p> <div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p> Remember sin(0) = 0, sin(pi) = 0, sin(2pi) = 0 etc</p> There are multiple solutions for x</p> </div></p> any within [pi/10, 3pi/10]?</p> i can't figure any out within those parameters. I don't think there is a right answer there.</p> </div></p> 2pi/10 because sin( 5*2pi/10) = sin(pi) = 0</p> </div></p> </p> SHIT!!!</p> my calculator was in degrees. Wow, I was wondering why it wasn't coming out right. Duh.</p> Don't know why it was degrees either...we never use degrees, always radians. Weird. Someone must've used it or something.</p> Oh well, thanks Cpaw and JCB.</p>
Damn cpaw beat me too it, and yes he's correct.</p> I just got back from school, so I can answer some questions if need be</p>
<div class='quotetop'>QUOTE (Kid Chocolate)</div><div class='quotemain'></p> The unit circle? oh boy... </p> </div></p> You're a member.</p> </p>
