x^3+5x^2=1 (x^2)(x+5)=1 That might be factorised better than before. (could take 1 from both sides obviously)
Can someone explain 4d? I've looked at the solution online but can't figure out what was done to arrive at the answer. Necesito help, por favor.
I think you will need to integrate f' to get f. Then plug in the two values. By my reckoning f'(x): y=-x-2 where -3\<x\<0 (x-2)^2+(y+2)^2=4 where 0\<x\<4 and y>/-2. So try integrating those, I think
Out of Laos Thailand North Vietnam South Vietnam China which ones were neutral, communist and the other one i forgot the name.
<div class='quotetop'>QUOTE (Bynumite @ Apr 1 2008, 10:42 PM) <{POST_SNAPBACK}></div><div class='quotemain'>Out of Laos Thailand North Vietnam South Vietnam China which ones were neutral, communist and the other one i forgot the name.</div> www.wikipedia.org
<div class='quotetop'>QUOTE (chingy0007 @ Mar 14 2008, 11:43 AM) <{POST_SNAPBACK}></div><div class='quotemain'>I think you will need to integrate f' to get f. Then plug in the two values. By my reckoning f'(x): y=-x-2 where -3\<x\<0 (x-2)^2+(y+2)^2=4 where 0\<x\<4 and y>/-2. So try integrating those, I think </div> nice. i guess they gave you f(0) because that way you can get both constants after the integrations.
